Calculate capacitance of solid conducting spheres and two concentric spherical shells,
C = 4π × 8,8541878128×10⁻¹² × 0,10 = 1,1126500555×10⁻¹¹ F = 11,1265 pF.
a·b/(b−a) = 0,05×0,10/0,05 = 0,10 m → C = 4πε₀ × 0,10 = 11,1265 pF — same as a solid sphere R = 10 cm.
C = 11.1265 pF at V = 1000 V → Q = C·V = 11,1265 nC; U = ½·C·V² = 5,56325 µJ. Field at r = 50 cm: E = (8.9875517923×10⁹)(11.1265×10⁻⁹)/0.25 = 400,0 V/m; right at the surface (r = 10 cm): 10 kV/m.
Cvakum = 11,1265 pF, κ = 2,1 → C = 2,1 × 11,1265 = 23,3657 pF.
C = 4 x pi x epsilon0 x R, with epsilon0 = 8.8541878128 x 10^-12 F/m. Capacitance scales linearly with radius:
| Sphere radius R | Capacitance C = 4πε₀R |
|---|---|
| 1 cm | 1.1127 pF |
| 5 cm | 5.5633 pF |
| 10 cm | 11.1265 pF |
| 50 cm | 55.6325 pF |
| 1 m | 111.265 pF |
Enter any of these radii in the Solid Sphere tab to confirm the table.
C = kappa x C_vacuum. The presets built into the Dielectric tab (vacuum is exactly 1 by definition):
| Material | Relative permittivity κ | Note |
|---|---|---|
| Vacuum | 1 | Exact, by definition |
| Air (STP) | about 1.0006 | Negligible effect at this precision |
| Teflon (PTFE) | 2.1 | Stable, common insulator |
| Mica | 6 (typical) | Real range about 3-7 by type; use custom κ for exact work |
Example: 11.1265 pF vacuum capacitance filled with Teflon becomes 2.1 x 11.1265 = 23.3657 pF.
The formula comes straight from Gauss's law, in four steps:
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C = 4 x pi x epsilon0 x a x b / (b - a), where a is the inner shell radius, b is the outer shell radius, and epsilon0 = 8.8541878128 x 10^-12 F/m. Try a = 5 cm, b = 10 cm in the Two Shells tab: the result is 11.1265 pF.
C = 4 x pi x epsilon0 x R. A sphere of radius R = 10 cm gives C = 4 x pi x 8.8541878128 x 10^-12 x 0.1 = 1.11265 x 10^-11 F = 11.1265 pF, exactly what the Solid Sphere tab shows.
From Gauss's law, the field between the shells (a < r < b) is E = Q / (4 x pi x epsilon0 x r^2). Integrating from a to b gives the voltage V = Q x (b - a) / (4 x pi x epsilon0 x a x b). Capacitance C = Q / V then yields C = 4 x pi x epsilon0 x a x b / (b - a).
8.8541878128 x 10^-12 F/m (CODATA 2018), the value this calculator uses. It is the proportionality constant linking electric charge to the electric field in vacuum.
Three inverse formulas, all in the Inverse tab: solid sphere R = C / (4 x pi x epsilon0); outer shell b = C x a / (C - 4 x pi x epsilon0 x a); inner shell a = C x b / (C + 4 x pi x epsilon0 x b). The outer-shell solution exists only if C exceeds the isolated-sphere capacitance of the inner shell.
Q = C x V and U = 1/2 x C x V^2. Example: C = 11.1265 pF at V = 1000 V stores Q = 11.1265 nC and U = 5.56325 microJ, as the Charge and Energy tab computes.
Outside the shells (r >= b), E = Q / (4 x pi x epsilon0 x r^2), the same as a point charge Q at the center. Inside a hollow conductor E = 0. Example: Q = 11.1265 nC gives E = 400.0 V/m at r = 50 cm and 10 kV/m right at a 10 cm surface.
C = kappa x C_vacuum, where kappa is the material's relative permittivity. Built-in presets: vacuum 1, air about 1.0006, Teflon (PTFE) 2.1, mica typically 6 (real range about 3-7 by type; enter a custom kappa for your exact material).
Because a x b / (b - a) = 0.05 x 0.10 / 0.05 = 0.10 m, which equals the solid sphere's radius. Both give C = 4 x pi x epsilon0 x 0.10 = 11.1265 pF. It is a coincidence of these particular numbers, not a general rule.
The formula approaches the parallel-plate result: C approx epsilon0 x A / d with A = 4 x pi x a^2 (the shell area) and d = b - a (the gap). The calculator's Two Shells tab notes this limit.
k = 1 / (4 x pi x epsilon0) = 8.9875517923 x 10^9 N m^2/C^2, derived from the same epsilon0 so every tab stays consistent.
Capacitance: F, mF, microF, nF, pF. Radius/length: mm, cm, m, inch. Charge: C, mC, microC, nC, pC. Results auto-format to the most readable unit.
It assumes two perfectly concentric thin spherical shells (or one isolated sphere) with a linear dielectric. It does not apply to non-concentric shells, non-spherical geometries, or nonlinear/ferroelectric dielectrics.
Energy density in the field is u = 1/2 x epsilon0 x E^2. Integrating u over all space outside the shells recovers exactly U = 1/2 x C x V^2, a good consistency check on the formulas.
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