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Spherical Capacitor Calculator

Calculate capacitance of solid conducting spheres and two concentric spherical shells,

C = 4πε₀R
Isolated solid sphere: all charge resides on the surface. For R = 1 111,265 pF.

Worked examples

1. Solid sphere R = 10 cm

C = 4π × 8,8541878128×10⁻¹² × 0,10 = 1,1126500555×10⁻¹¹ F = 11,1265 pF.

2. Two shells a = 5 cm, b = 10 cm

a·b/(b−a) = 0,05×0,10/0,05 = 0,10 m → C = 4πε₀ × 0,10 = 11,1265 pF — same as a solid sphere R = 10 cm.

3. Charge, energy, and field

C = 11.1265 pF at V = 1000 V → Q = C·V = 11,1265 nC; U = ½·C·V² = 5,56325 µJ. Field at r = 50 cm: E = (8.9875517923×10⁹)(11.1265×10⁻⁹)/0.25 = 400,0 V/m; right at the surface (r = 10 cm): 10 kV/m.

4. Dielektrik Teflon

Cvakum = 11,1265 pF, κ = 2,1 → C = 2,1 × 11,1265 = 23,3657 pF.

Capacitance Reference: Isolated Solid Sphere

C = 4 x pi x epsilon0 x R, with epsilon0 = 8.8541878128 x 10^-12 F/m. Capacitance scales linearly with radius:

Sphere radius RCapacitance C = 4πε₀R
1 cm1.1127 pF
5 cm5.5633 pF
10 cm11.1265 pF
50 cm55.6325 pF
1 m111.265 pF

Enter any of these radii in the Solid Sphere tab to confirm the table.

Dielectric Constant Reference

C = kappa x C_vacuum. The presets built into the Dielectric tab (vacuum is exactly 1 by definition):

MaterialRelative permittivity κNote
Vacuum1Exact, by definition
Air (STP)about 1.0006Negligible effect at this precision
Teflon (PTFE)2.1Stable, common insulator
Mica6 (typical)Real range about 3-7 by type; use custom κ for exact work

Example: 11.1265 pF vacuum capacitance filled with Teflon becomes 2.1 x 11.1265 = 23.3657 pF.

Deriving the Spherical Capacitor Formula

The formula comes straight from Gauss's law, in four steps:

  1. Field between shells: by spherical symmetry, E(r) = Q / (4 x pi x epsilon0 x r^2) for a < r < b.
  2. Voltage: V = integral of E from a to b = Q/(4 x pi x epsilon0) x (1/a - 1/b) = Q x (b - a)/(4 x pi x epsilon0 x a x b).
  3. Capacitance: C = Q/V = 4 x pi x epsilon0 x a x b/(b - a).
  4. Solid sphere limit: let b approach infinity and the formula reduces to C = 4 x pi x epsilon0 x a, the isolated-sphere result.

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Frequently Asked Questions About Spherical Capacitors

What is the capacitance formula for a spherical capacitor (two shells)?

C = 4 x pi x epsilon0 x a x b / (b - a), where a is the inner shell radius, b is the outer shell radius, and epsilon0 = 8.8541878128 x 10^-12 F/m. Try a = 5 cm, b = 10 cm in the Two Shells tab: the result is 11.1265 pF.

What is the capacitance of an isolated solid conducting sphere?

C = 4 x pi x epsilon0 x R. A sphere of radius R = 10 cm gives C = 4 x pi x 8.8541878128 x 10^-12 x 0.1 = 1.11265 x 10^-11 F = 11.1265 pF, exactly what the Solid Sphere tab shows.

How is the spherical capacitor formula derived?

From Gauss's law, the field between the shells (a < r < b) is E = Q / (4 x pi x epsilon0 x r^2). Integrating from a to b gives the voltage V = Q x (b - a) / (4 x pi x epsilon0 x a x b). Capacitance C = Q / V then yields C = 4 x pi x epsilon0 x a x b / (b - a).

What is epsilon0 (vacuum permittivity)?

8.8541878128 x 10^-12 F/m (CODATA 2018), the value this calculator uses. It is the proportionality constant linking electric charge to the electric field in vacuum.

How do you find a shell radius from a known capacitance?

Three inverse formulas, all in the Inverse tab: solid sphere R = C / (4 x pi x epsilon0); outer shell b = C x a / (C - 4 x pi x epsilon0 x a); inner shell a = C x b / (C + 4 x pi x epsilon0 x b). The outer-shell solution exists only if C exceeds the isolated-sphere capacitance of the inner shell.

What charge and energy are stored in a spherical capacitor?

Q = C x V and U = 1/2 x C x V^2. Example: C = 11.1265 pF at V = 1000 V stores Q = 11.1265 nC and U = 5.56325 microJ, as the Charge and Energy tab computes.

What is the electric field around a spherical capacitor?

Outside the shells (r >= b), E = Q / (4 x pi x epsilon0 x r^2), the same as a point charge Q at the center. Inside a hollow conductor E = 0. Example: Q = 11.1265 nC gives E = 400.0 V/m at r = 50 cm and 10 kV/m right at a 10 cm surface.

How does a dielectric affect a spherical capacitor?

C = kappa x C_vacuum, where kappa is the material's relative permittivity. Built-in presets: vacuum 1, air about 1.0006, Teflon (PTFE) 2.1, mica typically 6 (real range about 3-7 by type; enter a custom kappa for your exact material).

Why does a = 5 cm, b = 10 cm give the same capacitance as a solid 10 cm sphere?

Because a x b / (b - a) = 0.05 x 0.10 / 0.05 = 0.10 m, which equals the solid sphere's radius. Both give C = 4 x pi x epsilon0 x 0.10 = 11.1265 pF. It is a coincidence of these particular numbers, not a general rule.

What happens if the gap between shells is very thin?

The formula approaches the parallel-plate result: C approx epsilon0 x A / d with A = 4 x pi x a^2 (the shell area) and d = b - a (the gap). The calculator's Two Shells tab notes this limit.

What is the Coulomb constant used in the field calculation?

k = 1 / (4 x pi x epsilon0) = 8.9875517923 x 10^9 N m^2/C^2, derived from the same epsilon0 so every tab stays consistent.

What units does the calculator support?

Capacitance: F, mF, microF, nF, pF. Radius/length: mm, cm, m, inch. Charge: C, mC, microC, nC, pC. Results auto-format to the most readable unit.

When does the spherical capacitor formula not apply?

It assumes two perfectly concentric thin spherical shells (or one isolated sphere) with a linear dielectric. It does not apply to non-concentric shells, non-spherical geometries, or nonlinear/ferroelectric dielectrics.

What is the energy stored per unit volume?

Energy density in the field is u = 1/2 x epsilon0 x E^2. Integrating u over all space outside the shells recovers exactly U = 1/2 x C x V^2, a good consistency check on the formulas.

Is this spherical capacitor calculator free?

Yes, free and unlimited, running entirely in your browser with no server calls.

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