Compute the molecular mean free path λ = kB·T/(√2·π·d²·p) — from temperature, molecular diameter and pressure, or solve inversely for pressure or temperature. Includes gas presets, an everyday-object scale comparison, and collision-frequency readouts.
λ = kB·T / (√2·π·d²·p)
Mean free path from temperature, diameter and pressure
Pressure from mean free path
At what pressure do molecules travel a given mean free path?
Temperature from mean free path
At what temperature do molecules travel a given mean free path?
Worked example: air at STP
Air at standard temperature and pressure (T = 273.15 K, p = 101325 Pa) with kinetic diameter d = 0.37 nm:
The mean free path (λ) is the average distance a gas molecule travels between collisions with other molecules. In air at room temperature and atmospheric pressure it is only about 66.79 nm — far smaller than the wavelength of visible light. The mean free path grows as the gas gets thinner: at 100 Pa (a rough vacuum) it reaches 66.54 µm, and in outer space it can be kilometers.
What is the mean free path formula?
Kinetic theory gives λ = kB·T / (√2·π·d²·p), where kB = 1.380649×10⁻²³ J/K is the Boltzmann constant (exact), T is the absolute temperature in kelvin, d is the molecular (kinetic) diameter in meters, and p is the pressure in pascals. In molar form this is λ = R·T / (√2·π·d²·NA·p), with R the gas constant and NA Avogadro's number — the two forms are identical.
What is the mean free path of air at STP?
Using the kinetic diameter of air d = 0.37 nm, this calculator gives λ = 61.19 nm for air at STP (273.15 K, 101325 Pa), i.e. λ = 6.1192691616e-08 m. Textbooks often quote about 68 nm; the small difference comes from the choice of effective molecular diameter — 68 nm corresponds to d ≈ 0.35 nm. At 25 °C and 1 atm the same formula gives λ = 66.79 nm.
How does pressure affect the mean free path?
The mean free path is inversely proportional to pressure: halve the pressure and molecules travel twice as far between collisions (λ ∝ 1/p). For air at 20 °C, dropping the pressure from 1 atm to 100 Pa increases λ from 65.67 nm to 66.54 µm — a factor of about 1013. That is why vacuum chambers, high-altitude flight, and microdevices behave so differently from everyday atmospheric flows.
How does temperature affect the mean free path?
At constant pressure the mean free path is directly proportional to absolute temperature: heating the gas makes molecules faster and the gas less dense, so λ ∝ T. Warming air at 1 atm from 0 °C (273.15 K) to 25 °C (298.15 K) increases λ from 61.19 nm to 66.79 nm — a 9.2% increase for a 9.2% rise in absolute temperature.
What molecular diameter should I use?
Use the kinetic (collision) diameter of the gas. This calculator presets: air 0.370 nm, nitrogen (N₂) 0.364 nm, oxygen (O₂) 0.346 nm, hydrogen (H₂) 0.289 nm, helium (He) 0.260 nm, argon (Ar) 0.340 nm, carbon dioxide (CO₂) 0.394 nm. These are approximate literature values — the effective diameter depends on how it is measured (viscosity, diffusion, or molecular sieves can disagree by about 10%), which is why published mean free paths for the same gas vary slightly. You can also enter a custom diameter.
How many collisions does a molecule suffer per second?
The collision frequency is f = v̄/λ, where v̄ is the mean molecular speed. For air at STP this calculator gives a number density of 2.687e+25 molecules/m³ (Loschmidt's number), a mean speed of about 447 m/s, and f ≈ 7.302e+9 collisions per second — roughly 7.3 billion collisions every second for each molecule. That enormous rate is why gases reach equilibrium almost instantly at atmospheric pressure.
How is the mean free path related to the Knudsen number?
The Knudsen number is Kn = λ/L, the ratio of the mean free path to a characteristic length L (a channel height, particle diameter, or pipe diameter). It tells you which flow model to use: Kn < 0.01 is ordinary continuum flow, 0.01–0.1 is slip flow, 0.1–10 is the transition regime, and Kn ≥ 10 is free-molecular flow. Our Knudsen number calculator computes Kn directly from λ and L.
Why is there a √2 in the formula?
The √2 accounts for the fact that the target molecules are moving too, not sitting still. A molecule sweeping through stationary targets would travel 1/(n·π·d²) between hits, where n is the number density. Because all molecules move with an average relative speed √2 times the mean speed, collisions happen √2 times more often, shortening the mean free path by that factor. The formula also assumes hard-sphere molecules; it breaks down for very dense gases, liquids, and plasmas.
Which units does this calculator accept?
Temperature: kelvin (K) or degrees Celsius (°C). Pressure: pascals (Pa), kilopascals (kPa), bar, standard atmospheres (atm), or torr. Mean free path (inverse modes): nanometers (nm), micrometers (µm), millimeters (mm), or meters (m). Molecular diameter: enter in nanometers, or pick a gas preset. Results are shown in nm, µm, mm, and m side by side.
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