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Lever · Pulley · Inclined plane · Screw

Mechanical Advantage Calculator

How much does a simple machine multiply your force? Ideal MA is pure geometry — MA = F_out / F_in = d_in / d_out — and real machines multiply by efficiency: F_out = F_in × MA × η. Four modes, each with a 3-way solver (MA, effort, or load).

4simple machines
123-way solvers
10FAQs answered

01Calculator

Pick a machine. Each panel solves three ways: give the geometry and any one force, and the calculator finds MA, the output force, or the required effort.

L_in (effort arm) L_out (load arm) F_in F_out fulcrum
Fulcrum → effort point.
Fulcrum → load point.
—
fixed block moving block F_in n = 4 load F_out
Segments supporting the moving block.
—
h L F_in F_out
Along the ramp surface.
Must be ≤ slope length.
Push along the slope.
Weight lifted vertically.
—
lead r F_in F_out
Axis → hand grip.
Axial travel per revolution.
Tangential push at the handle.
Axial push of the screw.
—

02Worked examples

Every number below was recomputed against the engine on this page — plug them in to verify.

Lever: 2 m effort arm, 0.5 m load arm

MA = L_in / L_out = 2 / 0.5 = 4 F_out = F_in × MA × η = 50 × 4 × 1 = 200 N With pivot friction η = 0.85: 50 × 4 × 0.85 = 170 N
Ideal MA = 4 · 50 N effort → 200 N output (170 N real)

Pulley: 4 rope segments, 100 N effort

MA = n = 4 F_out = 100 × 4 × 0.85 = 340 N Rope trade-off: lifting the load 2 m needs 4 × 2 = 8 m of rope
F_out ≈ 340 N (600 N ideal with n = 6 at η = 1)

Inclined plane: 3 m ramp, 0.6 m rise

MA = L / h = 3 / 0.6 = 5 (slope angle arcsin(0.6/3) = 11.54°) F_out = 200 × 5 × 1 = 1,000 N ≈ 101.97 kgf
200 N along the slope lifts 1,000 N vertically

Screw: 200 mm handle, 5 mm lead

MA = 2πr / lead = 2π × 0.2 / 0.005 = 251.33 F_out = 50 × 251.33 × 0.35 = 4,398.23 N (lead screw) Ideal η = 1: 50 × 251.33 = 12,566.37 N
50 N at the handle → 4,398.23 N axial (real) · 12,566.37 N (ideal)

03Reference tables

Lever MA by arm ratio (50 N effort, η = 1)

Arm ratio L_in : L_outMAF_out
2 : 12100 N
3 : 13150 N
4 : 14200 N
5 : 15250 N
10 : 110500 N

Pulley MA by rope segments

Rope segments nIdeal MA≈ real MA (0.96ⁿ)Rope per 1 m lift
110.961 m
221.842 m
332.653 m
443.404 m
554.085 m
664.706 m

Typical efficiency η by machine

MachineTypical ηNotes
Lever / fulcrum0.95–1.0Pivot friction is small; use 0.97
Pulley (per sheave)≈ 0.96Total η ≈ 0.96ⁿ — 4 sheaves ≈ 0.85
Inclined plane0.85–0.95Rollers high, sliding friction low
Ball screw0.85–0.95Back-drivable; needs a brake to hold
Lead / Acme screw0.30–0.50Usually self-locking, runs hot

04Method & assumptions

Ideal MA is pure geometry: MA = F_out / F_in = d_in / d_out. Lever: L_in / L_out about the fulcrum. Pulley: n, the count of rope segments supporting the moving block (the free end counts when it pulls upward on the load). Inclined plane: L / h, slope length over vertical rise. Screw: 2πr / lead, handle circumference per turn over axial advance per turn.

Real machines: F_out = F_in × MA_ideal × η and F_in = F_out / (MA_ideal × η), with η in (0, 1]. Rope weight, stretch, lever flex, and thread backlash are not modeled — the efficiency factor is where those losses live.

Unit anchors (exact): 1 lbf = 4.4482216152605 N · 1 kgf = 9.80665 N · 1 in = 0.0254 m · 1 ft = 0.3048 m. MA itself is dimensionless, so mixed length units cancel as long as both arms use real conversions.

05Frequently asked questions

What is mechanical advantage?

Mechanical advantage (MA) is the factor by which a machine multiplies your input force: MA = F_out / F_in. For an ideal (frictionless) machine it also equals the distance ratio d_in / d_out — you trade force for distance, never get energy for free. Worked example (lever): effort arm 2 m, load arm 0.5 m, so MA = 2 / 0.5 = 4. A 50 N effort then produces F_out = 50 x 4 = 200 N at the load.

How do I calculate the mechanical advantage of a lever?

Divide the effort arm by the load arm: MA = L_in / L_out, both measured from the fulcrum. Worked example: 2 m effort arm, 0.5 m load arm -> MA = 4. Class matters for direction: a class-1 lever (fulcrum between effort and load, like a crowbar) reverses direction; class-2 (load between fulcrum and effort, like a wheelbarrow) and class-3 (effort between fulcrum and load, like tweezers) keep the same direction. The formula MA = L_in / L_out holds for all three classes.

Why is my actual force lower than ideal MA times effort?

Friction, rope stretch, and deformation eat part of the work. The real relation is F_out = F_in x MA_ideal x eta, where eta is efficiency (0-1). Worked example: 50 N effort, ideal MA 4, eta = 0.85 -> F_out = 50 x 4 x 0.85 = 170 N, not 200 N. Equivalently the actual MA is 4 x 0.85 = 3.4... precisely 3.40. Enter your best efficiency estimate in the calculator; the Ideal vs Actual columns show both.

How does a pulley system multiply force?

Count the rope segments supporting the moving block (including the free end if it pulls up on the load): MA = n. Worked example: n = 4, 100 N effort, eta = 0.85 -> F_out = 100 x 4 x 0.85 = 340 N. Ideal (eta = 1) with n = 6 gives 600 N from 100 N. The trade-off is rope: to lift the load 2 m with n = 4 you must pull 8 m of rope (distance ratio = n). Each sheave loses roughly 4% (eta ~0.96 per sheave); a 3-sheave lashing tackle with 80 N effort gives 80 x 3 x 0.96^3 = 212.34 N.

What is the mechanical advantage of an inclined plane?

MA = L / h: slope length divided by vertical rise. Worked example: a 3 m ramp rising 0.6 m -> MA = 3 / 0.6 = 5, so 200 N of push up the slope lifts F_out = 200 x 5 = 1,000 N (about 101.97 kgf). The slope angle is arcsin(0.6/3) = 11.54 degrees. With rolling/sliding efficiency eta = 0.95, lifting 1,000 N needs F_in = 1,000 / (5 x 0.95) = 210.53 N. A longer, shallower ramp always means less force but a longer push.

How do you calculate the mechanical advantage of a screw?

One turn of the handle moves your hand through a circumference 2 x pi x r while the load advances one lead: MA = 2 x pi x r / lead. Worked example: handle radius r = 0.2 m, lead = 5 mm -> MA = 2 x pi x 0.2 / 0.005 = 251.33. With 50 N at the handle and a sliding-screw efficiency of 0.35: F_out = 50 x 251.33 x 0.35 = 4,398.23 N (ideal eta = 1 would be 12,566.37 N). A finer thread multiplies harder: r = 150 mm with a 2 mm lead gives MA = 471.24, turning 30 N into 5,654.87 N at eta = 0.4.

Can mechanical advantage be less than 1?

Yes — then the machine is a speed/distance multiplier instead of a force multiplier. Worked example: effort arm 0.75 m, load arm 1.5 m -> MA = 0.75 / 1.5 = 0.5, so 10 N of effort moves a 5 N load, but the load travels twice as far and twice as fast as your hand. Class-3 levers (tweezers, fishing rods, the human forearm) and overdrive gears live in this regime. The same force equations apply unchanged; the calculator handles MA < 1 in every mode.

How do I solve for the effort force I need?

Rearrange to F_in = F_out / (MA_ideal x eta) and use the Effort solver tab. Worked example: you must lift 1,000 N with a screw of MA 251.33 at eta = 1 -> F_in = 1,000 / 251.33 = 3.98 N at the handle. Lever check: to get 200 N out of a 4:1 lever at eta = 1 you need 200 / 4 = 50 N in — the inverse of the anchor example. Always include efficiency: ignoring it underestimates the required effort.

What efficiency should I assume for each simple machine?

Honest defaults: lever and fulcrum 0.95-1.0 (pivot friction is tiny); pulley about 0.96 per sheave, so eta_total ~ 0.96^n — four sheaves give ~0.85, which is why the worked n = 4 example uses eta = 0.85; inclined plane 0.85-0.95 depending on rollers vs sliding friction and lubrication; screw: ball screw 0.85-0.95, sliding/Acme lead screw 0.3-0.5 (self-locking but lossy). When unsure, derate one step: the calculator shows ideal and actual side by side so you can see the cost of optimism.

How is this different from a powered actuator force calculator?

This tool covers simple machines — levers, pulleys, ramps, screws — where a human-scale effort force is the input and geometry sets the ideal MA. Powered actuators start from pressure or motor torque instead: for hydraulic/pneumatic cylinders (F = P x A, push and pull) and electric screw actuators (F = 2 x pi x T x eta / lead), use the companion Linear Actuator Force Calculator. The screw mode here and the screw actuator there share the same physics; the difference is whether your input is hand force at a handle or motor torque at a shaft.

06Related tools

Sizing a powered actuator instead of a hand-driven simple machine? Start here:

Linear Actuator Force Calculator — F = P × A for hydraulic/pneumatic cylinders (push and pull) and F = 2πTη/lead for electric screw actuators, with 3-way solvers.

Free tool by NRTechStudio