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Insertion Loss Calculator

Calculate insertion loss from power or voltage measurements — in dB, with a 3-way solver, dB ↔ linear-ratio conversion, and multi-stage cascade summation. 100% runs in your browser.

IL power: 10·log₁₀(Pin/Pout)IL voltage: 20·log₁₀(Vin/Vout)Cascade: Σ IL
What to calculate? (3-way solver)

Formula: IL = 10 · log₁₀(Pin / Pout). With dBm units, IL = Pin(dBm) − Pout(dBm) directly (e.g. 30 dBm → 27 dBm = 3 dB). Negative values mean gain.

What to calculate? (3-way solver)

Formula: IL = 20 · log₁₀(Vin / Vout) — only valid when input impedance equals output impedance. If impedances differ, measure power (watts) and use the Power tab.

dB → linear ratio

Linear ratio → dB

Power ratio = 10dB/10 · Voltage ratio = 10dB/20. Example: 10 dB → power ratio 10 : 1, voltage ratio 3.1623 : 1.

Sum the insertion loss of each cascaded stage. Negative value = gain stage.

ILtotal = Σ ILi. Example: 3 + 2 + 1.5 = 6.5 dB → overall power ratio 4.4668 : 1.

One-click examples

Example results: 1 W → 0.5 W gives 3.0103 dB (half the power lost). 2 V → 1 V gives 6.0206 dB (factor 20, not 10, because it is voltage). Cascade 3 + 2 + 1.5 dB = 6.5 dB total.

Quick reference table

Insertion lossPower ratioPower throughVoltage ratio
0.5 dB1.1220 : 189.13 %1.0593 : 1
1 dB1.2589 : 179.43 %1.1220 : 1
1.5 dB1.4125 : 170.79 %1.1885 : 1
3 dB1.9953 : 150.12 %1.4125 : 1
3.0103 dB2.0000 : 150.00 %1.4142 : 1
6 dB3.9811 : 125.12 %1.9953 : 1
6.02 dB3.9994 : 125.00 %1.9999 : 1
10 dB10.0000 : 110.00 %3.1623 : 1
20 dB100.0000 : 11.00 %10.0000 : 1
30 dB1000.0000 : 10.10 %31.6228 : 1
Scope boundary vs Pi/T Attenuator Designer: this tool calculates insertion loss from measured results or Pin/Pout ratios. To design Pi/T attenuator resistor values from a target dB, use Pi/T Attenuator Designer.
Scope boundary vs Distance Attenuation: this tool covers insertion loss of RF-electronic circuits/components. For sound attenuation over distance (acoustics), use Distance Attenuation.

Frequently asked questions (FAQ)

What is insertion loss?
Insertion loss (IL) is the power lost when a device is inserted into a transmission path, expressed in decibels (dB). It is calculated as IL = 10 · log₁₀(Pin / Pout) for power. Example: 1 W in and 0.5 W out gives 10 · log₁₀(2) = 3.0103 dB.
What is the difference between insertion loss and return loss?
Insertion loss measures power lost through the device (transmitted signal), while return loss measures power reflected back toward the source due to impedance mismatch (RL = −20·log₁₀|Γ|). A device can have low insertion loss but poor return loss, or vice versa — they describe different loss mechanisms.
Why does the power formula use 10·log₁₀ but the voltage formula uses 20·log₁₀?
Because power is proportional to voltage squared (P = V²/R). Taking the log: log₁₀(V²) = 2·log₁₀(V), which moves the factor 2 in front: 10 × 2 = 20. Both formulas measure the same physical loss when impedances are equal — halving the power (3.0103 dB) also halves the voltage-squared, i.e. voltage drops by √2, and 20·log₁₀(√2) = 3.0103 dB. Identical.
Can insertion loss be negative?
Yes. Negative insertion loss means gain — the output exceeds the input, as with an amplifier (a −10 dB "loss" is a 10 dB gain). For passive devices (cables, connectors, filters, attenuators), insertion loss is always zero or positive.
How do I calculate insertion loss from dBm readings?
Simply subtract: IL = Pin(dBm) − Pout(dBm), because dBm is already logarithmic. Example: 30 dBm in and 27 dBm out gives exactly 3 dB of insertion loss — no log math needed.
How do you add insertion loss in a cascade of stages?
Add the decibel values: ILtotal = Σ ILi. Example: stages of 3 dB + 2 dB + 1.5 dB give 6.5 dB total, which equals an overall power ratio of 4.4668 : 1. Never add the linear ratios — always sum in dB, then convert once at the end if needed.
What does 3 dB of insertion loss mean?
It means half the power is lost (a 2 : 1 power ratio; 50% gets through). Precisely, 3.0103 dB equals exactly half power. Similarly, 10 dB means one-tenth of the power remains (90% lost) and 20 dB means one-hundredth remains.
Is insertion loss the same as attenuation?
They are related but not identical. Attenuation is the general term for any signal-level reduction (by distance, cable, or components). Insertion loss is specifically the attenuation caused by inserting a device into the line. This calculator computes insertion loss from measured Pin/Pout; to design resistor values for a Pi/T attenuator, use our Pi/T Attenuator Designer instead.
Does the voltage formula require matched impedance?
Yes — IL = 20·log₁₀(Vin/Vout) is only valid when the input and output impedances are equal. If they differ, measure power in watts and use the power formula 10·log₁₀(Pin/Pout), which is always correct.
How do I convert insertion loss in dB to a linear ratio?
Power ratio = 10dB/10 and voltage ratio = 10dB/20. Example: 10 dB converts to a power ratio of 10 : 1 and a voltage ratio of 3.1623 : 1. Going the other way: dB = 10·log₁₀(power ratio) = 20·log₁₀(voltage ratio).

See also

Free tool by NRTechStudio